sorry > You compare a module.CONSTANT to the result of an expression
s/an expression/a binary operation/ /joel Joel Hedlund wrote: >>If it weren't for the current CPython optimization (caching small >>integers) > > > This has already been covered elsewhere in this thread. Read up on it. > > >>this code which it appears you would support writing >> >> if (flags & os.R_OK) is os.R_OK: > > > I do not. > > You compare a module.CONSTANT to the result of an expression (flags & > os.R_OK). > Expressions are not names bound to objects, the identity of which is what I'm > talking about. This example does not apply. Also, the identity check in my > example has a value equality fallback. Yours doesn't, so it really does not > apply. > > > (I think you should give it up... you're trying to push a rope.) > > I'm not pushing anything. I just don't like being misquoted. > > Cheers, > Joel Hedlund -- http://mail.python.org/mailman/listinfo/python-list
