"dongdong" <[EMAIL PROTECTED]> wrote in message news:[EMAIL PROTECTED] > for example: > re.sub('<a( [^>]+)+\s?>[^<^>]*</a>','',' asd ga<a target="_blank" > href="http://www.sine.com"; class="wordstyle"> asdgasdghae rha</a>') > > I wish to get the return value "asd ga asdgasdghae rha",how do do? > I have a impression on "%" and "{number}",but forgot how to use them. >
Well, here's the pyparsing rendition (two, actually). I hope it's easier to follow then trying to pick apart the above regexp. Both Download pyparsing at http://pyparsing.sourceforge.net. -- Paul instr = """' asd ga<a target="_blank" href="http://www.sine.com"; class="wordstyle"> asdgasdghae rha</a>'""" from pyparsing import makeHTMLTags,Suppress,MatchFirst # makeHTMLTags returns a tuple of the start and end pattern for the given tag aStart,aEnd = makeHTMLTags("a") # define a filter that will suppress the opening and closing tags # this is easily extended to filter additional patterns, too filter = Suppress(aStart) | Suppress(aEnd) # invoke transformString using the filter print filter.transformString(instr) # or for the dense-code minded... filter = MatchFirst( map( Suppress, makeHTMLTags("a") ) ) print filter.transformString(instr) Prints: ' asd ga asdgasdghae rha' ' asd ga asdgasdghae rha' -- http://mail.python.org/mailman/listinfo/python-list
