John McMonagle wrote:
> Say I have a dictionary like below:
>
> d = {(100,500):[5,5], (100,501):[6,6], (100,502):[7,7]}
>
> Say I want to multiply all the values of the dictionary by 2:
> for key in d.keys():
> d[key] = map(lambda x: x*2, d.get(key))
> Is there a better/faster/cleaner way to achieve this ?
To update, I'd either go with that or Felipe's list comprehension.
If you just want the value of the result, how about:
doubled = dict((key, [x * 2 for x in values])
for key, values in d.iteritems())
--
-Scott David Daniels
[EMAIL PROTECTED]
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