Michael Yanowitz wrote:
> Why is it 8 bytes in the third case and why would it be only 6 bytes
> in the last case if it is 8 in the previous?
>From TFM:
"""
Native size and alignment are determined using the C compiler's sizeof
expression. This is always combined with native byte order.
Standard size and alignment are as follows: no alignment is required for
any type (so you have to use pad bytes); short is 2 bytes; int and long are
4 bytes; long long (__int64 on Windows) is 8 bytes; float and double are
32-bit and 64-bit IEEE floating point numbers, respectively
"""
See this how to achieve the desired results (on my system at least):
>>> print struct.calcsize("I")
4
>>> print struct.calcsize("H")
2
>>> print struct.calcsize("HI")
8
>>> print struct.calcsize("=HI")
6
>>> print struct.calcsize("=IH")
6
>>>
Regards,
Diez
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