Hi Michael, Normalizing the whitespace is what I was looking to do. I guess that that aspect of my original query was not enough clear. But with either solutions, I get the result I wanted.
Greetings, Olivier Langlois http://www.quazal.com > -----Original Message----- > Fredrik Lundh wrote: > > > > >>>> " hello world ".split() > > ['hello', 'world'] > > a.split() == b.split() is a convenient test, provided you want to > normalize > whitespace rather than ignore it. I took the OP's requirements to mean > that > 'A B' == 'AB', but this is just a guess. > > > Michael -- http://mail.python.org/mailman/listinfo/python-list
