Hi folks! For debugging purposes I tried this:
--- snip --- def foo(): pass function = type(foo) class PrintingFunction(function): def __init__(self, func): self.func = func def __call__(self, *args, **kwargs): print args, kwargs return function.__call__(self, args, kwargs) class DebugMeta(type): def __new__(self, name, bases, dict): for name in dict: if type(dict[name]) is function: dict[name] = PrintingFunction(dict[name]) --- snap --- Now I tought I were able to let all maethod of classes with DebugMeta as metaclass print out their arguments. But I got the following sad error: TypeError: Error when calling the metaclass bases type 'function' is not an acceptable base type That's awful, isn't it? What could I do to get the above code working? (No, I disliked to re- implement <type 'function'> without this unpleasant behaviour in Python.) Greetings, F. Sidler -- http://mail.python.org/mailman/listinfo/python-list