"the.theorist" wrote:
> I used this bit of code to detect wether i want stdinput or not.
>
> if len(args)==0:
> args = [ sys.stdin ]
>
> Now in my main loop I've written:
>
> for file in args:
> for line in open( file ):
> #do stuff
>
> The probelm occurs when I pass no arguments and python trys to open(
> sys.stdin ).
> open() customarily accepts a pathname, and returns a file object.
> But this code is so elegant I thought that maybe, if open were passed
> file object it could re-open that file in a new mode (if a mode was
> provided different from the current mode) or simply return the file
> object it was passed.
so use your own open function:
def myopen(file):
if isinstance(file, basestring):
return open(file)
return file
for file in args:
for line in myopen( file ):
#do stuff
or perhaps
def myopen(file):
if hasattr(file, "read"):
return file
return open(file)
...
or perhaps
if not args:
args = [ "-" ]
def myopen(file):
if file == "-":
return sys.stdin
return open(file)
for file in args:
for line in myopen( file ):
#do stuff
(the "-" = stdin convention is quite common)
</F>
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