Paul Rubin wrote: > Hmm (untested, like above): > > class Synchronized: > def __init__(self, generator): > self.gen = generator > self.lock = threading.Lock() > def next(self): > self.lock.acquire() > try: > yield self.gen.next() > finally: > self.lock.release() > > synchronized_counter = Synchronized(itertools.count()) > > That isn't a general solution but can be convenient (if I didn't mess > it up). Maybe there's a more general recipe somewhere.
This code is not allowed in Python 2.4. From PEP 255: Restriction: A yield statement is not allowed in the try clause of a try/finally construct. The difficulty is that there's no guarantee the generator will ever be resumed, hence no guarantee that the finally block will ever get executed; that's too much a violation of finally's purpose to bear. Even if this was allowed, ISTM the semantics might be the same as your previous attempt - I would expect the finally to be executed after the yield returns, meaning the lock would be held during the yield. Python 2.5 will allow this (see PEP 342) but from the examples it seems the finally won't execute until the yield returns. Kent -- http://mail.python.org/mailman/listinfo/python-list
