fortepianissimo wrote:
> Hm this doesn't work. Say I have the following directory structure:
> A
> |--- util
> | |--- foo.py
> |
> |--- B
> |--- bar.py
>
> And bar.py has this line
>
> from util import foo
>
> I then run
>
> python B/bar.py
>
> in directory A. Still got error
>
> ImportError: No module named util
Do you have a file util/__init__.py? This is required to make python
recognize util as a package.
This works for me:
C:\WUTemp\A>dir /b/s
C:\WUTemp\A\B
C:\WUTemp\A\util
C:\WUTemp\A\B\bar.py
C:\WUTemp\A\B\__init__.py
C:\WUTemp\A\util\foo.py
C:\WUTemp\A\util\foo.pyc
C:\WUTemp\A\util\__init__.py
C:\WUTemp\A\util\__init__.pyc
C:\WUTemp\A>type util\foo.py
def baz():
print 'foo.baz() here'
C:\WUTemp\A>type B\bar.py
import sys
print sys.path
from util import foo
foo.baz()
C:\WUTemp\A>python B\bar.py
['C:\\WUTemp\\A\\B', 'C:\\Python24\\python24.zip', 'C:\\WUTemp\\A',
<snip lots more dirs>]
foo.baz() here
Kent
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