fortepianissimo wrote: > Hm this doesn't work. Say I have the following directory structure: > A > |--- util > | |--- foo.py > | > |--- B > |--- bar.py > > And bar.py has this line > > from util import foo > > I then run > > python B/bar.py > > in directory A. Still got error > > ImportError: No module named util
Do you have a file util/__init__.py? This is required to make python recognize util as a package. This works for me: C:\WUTemp\A>dir /b/s C:\WUTemp\A\B C:\WUTemp\A\util C:\WUTemp\A\B\bar.py C:\WUTemp\A\B\__init__.py C:\WUTemp\A\util\foo.py C:\WUTemp\A\util\foo.pyc C:\WUTemp\A\util\__init__.py C:\WUTemp\A\util\__init__.pyc C:\WUTemp\A>type util\foo.py def baz(): print 'foo.baz() here' C:\WUTemp\A>type B\bar.py import sys print sys.path from util import foo foo.baz() C:\WUTemp\A>python B\bar.py ['C:\\WUTemp\\A\\B', 'C:\\Python24\\python24.zip', 'C:\\WUTemp\\A', <snip lots more dirs>] foo.baz() here Kent -- http://mail.python.org/mailman/listinfo/python-list