On Sat, 04 Mar 2006 08:54:33 -0800, s99999999s2003 wrote:
> hi
>
> i have a file with
>
> xxx.xxx.xxx.xxx:yyy
> xxx.xxx.xxx.xxx:yyy
> xxx.xxx.xxx.xxx:yyy
> xxx.xxx.xxx.xxx
> xxx.xxx.xxx.xxx
> xxx.xxx.xxx.xxx:yyy
>
> i wanna split on ":" and get all the "yyy" and print the whole line out
> so i did
>
> print line.split(":")[-1]
>
> but line 4 and 5 are not printed as there is no ":" to split. It should
> print a "blank" at least.
> how to print out lines 4 and 5 ?
> eg output is
>
> yyy
> yyy
> yyy
>
>
> yyy
There are a few ways of handling this problem. It depends on what you want
to do if your input string looks like this "abc:y:z": should your code
print "y", "z" or even "y:z"?
# look before you leap
line = "abc:y:z"
if ":" in line:
print line.split(":")[-1] # prints "z"
print line.split(":")[1] # prints "y"
print line.split(":", 1)[-1] # prints "y:z"
# if your line only has one colon, the above three lines
# should all print the same thing
else:
print ""
# look before you leap again
L = line.split(":")
if len(L) > 1:
print L[1]
else:
print ""
# use a sentinel value
print (line + ":").split(":", 1)[1][:-1]
--
Steven.
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