Um, what about: for oindex in xrange(len(list)): object = list[oindex] print oindex
You can't create a generic function for this. Sebastjan On 3/3/06, William Meyer <[EMAIL PROTECTED]> wrote: > hi, > > I need to get the index of an object in a list. I know that no two objects > in the list are the same, but objects might evaluate as equal. for example > > list = [obj1, obj2, obj3, obj4, obj5] > for object in list: > objectIndex = list.index(object) > print objectIndex > > prints 0, 1, 2, 3, 2 instead of 0, 1, 2, 3, 4 because obj3 == obj5. I could > loop > through the list a second time comparing id()'s > > for object in list: > objectIndex = 0 > for i in list: > if id(object) == id(i): > break > objectIndex += 1 > print objectIndex > > but that seems like a real ugly pain. Somewhere, someplace python is keeping > track of the current index in list, does anyone know how to access it? Or have > any other suggestions? > > -- > http://mail.python.org/mailman/listinfo/python-list > -- http://mail.python.org/mailman/listinfo/python-list
