Benjamin Niemann wrote: > Byte wrote: > > > How can I make the following code: > > > > from random import random > > > > > > > > def stuff(a, mx): > > x = 2 > > while x == 2: > > x = random() > > if x == mx: print x > > else: print 'No luck,', x > > x = 2 > > > > Stop when x == mx? > > What's the intention behind setting x = 2 at all? > > def stuff(a, mx): > while True: > x = random() > if x == mx: print x > else: print 'No luck,', x > > Should do the same as you're code above. > > If stuff will never be called with mx=None, I would suggest using > > def stuff(a, mx): > x = None > while x != mx: > x = random() > if x == mx: print x > else: print 'No luck,', x > > Also note that random() returns a float and it is *very* unlikely that the > condition x == mx will ever come true
Right! And as for stopping use 'return' after your print statement to exit. -- http://mail.python.org/mailman/listinfo/python-list
