On Tue, 14 Feb 2006 14:29:44 +0300, Sergey wrote:
> Hello.
>
> I try to open file with pathname length 282 bytes:
> E:\files\..................\something.dat
>
> On MSDN
> (http://msdn.microsoft.com/library/default.asp?url=/library/en-us/fileio/fs/naming_a_file.asp)
> described method to access
> files with path length
> up to 32000 bytes: just add prefix \\?\ to file name.
> But when I try to pass prefixed name to file(), I get the same result as when
> I don't add the prefix: file not found. May be Python
> just doesn't support long unicode filenames?
> Is there way to open such files?
Backslashes have special meaning to Python and need to be escaped. If you
do this:
f = file("E:\files\...\something.dat", "r")
Python's string escape rules means you are actually trying to open the
file "E:files...something.dat" which doesn't exist.
You should escape the backslashes:
f = file("E:\\files\\...\\something.dat", "r")
or use raw strings:
f = file(r"E:\files\...\something.dat", "r")
or just use forward slashes and let Windows deal with it:
f = file("E:/files/.../something.dat", "r")
Does this help?
--
Steven.
--
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