"> Lonnie Princehouse wrote: >> Calling the wrapped version of this function from Python will produce a >> Python wrapper which represents the same underlying C++ object, but is >> not actually the same Python object:
What I think you need is a custom version of the .__eq__ (self,other) method that pierces thru the wrappers to compare the underlying C++ objects. Then test a == b. In Python, 'is' specifically means identity of Python objects. -- http://mail.python.org/mailman/listinfo/python-list
