On Sat, 11 Feb 2006 01:37:59 +0100 in comp.lang.python, Schüle Daniel
<[EMAIL PROTECTED]> wrote:
>Lonnie Princehouse wrote:
>> everybody is making this way more complicated than it needs to be.
>>
>> storage = list[:list.index(O)]
>
>the question is whether the old list is needed in the future or not
>if not then it would be easer/mor efficient to use
>
>del lst[lst.index(0):]
And you're both forgetting the list can end with X. the index method
raises a ValueError exception if the desired value is not found in the
list. Assuming you want to keep the original list and create a new
list called storage, you could try
if lst[-1] == X:
storage = lst[:]
else:
storage = lst[:lst.index(O)]
or even
try:
storage = lst[:lst.index(O)]
except ValueError:
storage = lst[:]
(WARNING: untested!)
Regards,
-=Dave
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