[EMAIL PROTECTED] wrote:
> i am having a problem writing a tuple to a text file. my code is
> below.
>
> what i end up getting is a text file that looks like this
>
> burger, 7up
> burger, 7up
> burger, 7up
>
> and this is instead of getting a list that should look like this
>
> burger, 7up
> fries ,coke
> cake ,milk
>
> note that i have print statements that print out the results of the
> scraping and they are fine. they print out burger, fries, cake and
> then 7up, coke, milk
>
> however there is something faulty in my writing of the tuple to the
> text file. perhaps related to the indentation that causes it to write
> the same stuff over and over?
>
>
>
> for row in bs('div'):
What kind of function is 'bs'? Should you use 'row'
(which you are looping over) inside the loop?
Seems that your code is equal to
for row in range(len(bs('div'))):
> for incident in bs('span'):
Just like you use 'incident' here, inside the other loop.
> foodlist = []
> b = incident.findPrevious('b')
> for oText in b.fetchText( oRE):
> #foodlist.append(oText.strip() + "',")
> foodlist += oText.strip() + "','"
> food = ''.join(foodlist)
> print food
>
After "print food" you repeat the loop, overwriting "food" until last
round. And after you have found the last "food", you put it in "tuple".
> tuple = (food + drink "\n")
A tip: 'tuple' is a built-in function, just like 'open' you use.
This statement overwrites that function with a string.
It is usually a good idea to leave the built-ins as they are,
and use some other names for variables.
--
http://mail.python.org/mailman/listinfo/python-list
