JerryB wrote:
> Hi,
> I have a dictionary, a string, and I'm creating another string, like
> this:
>
> dict = {}
> dict[beatles] = "need"
> str = "love"
>
> mystr = """All you %(dict[beatles])s is %(str)s""" % locals()
>
> Why do I get
> keyerror: 'dict[one]'?
>
> Is there a way to reference the elements in a dictionary with locals()
> or do I need to create a temp variable, like
>
> need = dict[one]
> mystr = """All you %(need)s is %(str)s"""
1) Avoid variable names like 'dict' and 'str'- they cover up the builtin
names.
2) When showing error, don't retype - cut and paste:
>>> dict[beatles] = "need"
Traceback (most recent call last):
File "<pyshell#6>", line 1, in -toplevel-
dict[beatles] = "need"
NameError: name 'beatles' is not defined
>>> dict['beatles'] = "need"
>>>
3) In string formating, the item in parenthesis, used as a string, is
the key for the dictionary. That is:
"""All you %(dict[beatles])s is %(str)s""" % ld
is the same as
"""All you %s is %s""" % (ld['dict[beatles]'],ld['str'])
4) Your best bet is not to use locals(), but to create a new dictionary
with the appropriate keys. E.g.:
>>> d = {}
>>> d['beatles'] = "need"
>>> s = "love"
>>> d2 = d.copy()
>>> d2['str'] = s
>>> d['str']
Traceback (most recent call last):
File "<pyshell#24>", line 1, in -toplevel-
d['str']
KeyError: 'str'
>>> d2['str']
'love'
>>> mystr = """All you %(beatles)s is %(str)s""" % d2
>>> print mystr
All you need is love
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