"Fredrik Lundh" <[EMAIL PROTECTED]> wrote in message news:[EMAIL PROTECTED] > Roger L. Cauvin wrote: > >> > $ python test.py >> > got expected >> > --------------- >> > accept accept >> > reject reject >> > accept accept >> > reject reject >> > accept accept >> >> Thanks, but the second test case I listed contained a typo. It should >> have >> contained a sequence of three of the letter 'a'. The test cases should >> be: >> >> "xyz123aaabbab" accept >> "xyz123aabbaaab" reject >> "xayz123aaabab" accept >> "xaaayz123abab" reject >> "xaaayz123aaabab" accept >> >> Your pattern fails the second test. > > $ more test.py > > import re > > print "got expected" > print "------ --------" > > testsuite = ( > ("xyz123aaabbab", "accept"), > ("xyz123aabbaaab", "reject"), > ("xayz123aaabab", "accept"), > ("xaaayz123abab", "reject"), > ("xaaayz123aaabab", "accept"), > ) > > for string, result in testsuite: > m = re.search("a+b", string) > if m and len(m.group()) == 4: > print "accept", > else: > print "reject", > print result > > $ python test.py > > got expected > ------ -------- > accept accept > reject reject > accept accept > reject reject > accept accept
Thanks, but I'm looking for a solution in terms of a regular expression only. In other words, "accept" means the regular expression matched, and "reject" means the regular expression did not match. I want to see if I can fulfill the requirements without additional code (such as checking "len(m.group())"). -- Roger L. Cauvin [EMAIL PROTECTED] (omit the "nospam_" part) Cauvin, Inc. Product Management / Market Research http://www.cauvin-inc.com -- http://mail.python.org/mailman/listinfo/python-list
