On Tue, 24 Jan 2006 08:45:27 -0600, Tim Chase wrote: > To get them in a key-order, my understanding is that you have to > use something like > > keys = mydict.keys() > sort(keys) > orderedDict = [(k, mydict[k]) for k in keys]
Did you test this before posting? >>> keys = ["a", "b"] >>> sort(keys) Traceback (most recent call last): File "<stdin>", line 1, in ? NameError: name 'sort' is not defined sort is not a built-in function. What you want is to call the sort method of the list: keys.sort() The sort method is always in-place, it does NOT return the newly sorted list. If you are using Python 2.4 or up, you can call the function sorted(keys) which leaves the original list as is, creates a copy, and sorts the copy. > unless you have a way of doing an in-line sort, in which you would be > able to do something like > > orderedDict = [(k,mydict[k]) for k in mydict.keys().sort()] > > Unfortunately, the version I've got here doesn't seem to support a > sort() method for the list returned by keys(). :( Remember, list.sort() does NOT return the list. It returns None. What you are doing there is sorting the keys, throwing the sorted list away, and trying to iterate over None. -- Steven. -- http://mail.python.org/mailman/listinfo/python-list
