Another try:
def flatten6(x, y):
return list(chain(*izip(x, y)))
(any case, this is shorter ;-)
Cyril
On 1/12/06, Michael Spencer <[EMAIL PROTECTED]> wrote:
> Tim Hochberg wrote:
> > Michael Spencer wrote:
> >> > Robin Becker schrieb:
> >> >> Is there some smart/fast way to flatten a level one list using the
> >> >> latest iterator/generator idioms.
> >> ...
> >>
> >> David Murmann wrote:
> >> > Some functions and timings
> >> ...
> >
> > Here's one more that's quite fast using Psyco, but only average without it.
> >
> >
> > def flatten6():
> > n = min(len(xdata), len(ydata))
> > result = [None] * (2*n)
> > for i in xrange(n):
> > result[2*i] = xdata[i]
> > result[2*i+1] = ydata[i]
> >
> > -tim
> >
> Indeed:
>
> I added yours to the list (after adding the appropriate return)
>
> >>> testthem()
> >>> timethem()
> flatten1(...) 702 iterations, 0.71msec per call
> flatten2(...) 641 iterations, 0.78msec per call
> flatten3(...) 346 iterations, 1.45msec per call
> flatten4(...) 1447 iterations, 345.66usec per call
> flatten5(...) 1218 iterations, 410.55usec per call
> flatten6(...) 531 iterations, 0.94msec per call
> >>>
>
> (See earlier post for flatten1-5)
>
> Michael
>
> --
> http://mail.python.org/mailman/listinfo/python-list
>
--
http://mail.python.org/mailman/listinfo/python-list
