On Wed, 04 Jan 2006 22:38:06 -0500,
"Stuart D. Gathman" <[EMAIL PROTECTED]> wrote:
> On Wed, 04 Jan 2006 10:54:17 -0800, KraftDiner wrote:
>> I was under the assumption that everything in python was a refrence...
>>
>> so if I code this:
>> lst = [1,2,3]
>> for i in lst:
>> if i==2:
>> i = 4
>> print lst
>>
>> I though the contents of lst would be modified.. (After reading that
>> 'everything' is a refrence.)
>> ...
>> Have I misunderstood something?
> It might help to do a translation to equivalent C:
> int _i1 = 1;
> int _i2 = 2;
> int _i3 = 3;
> int _i4 = 4;
> int* lst[NLST] = { &_i1,&_i2,&_i3 };
Okay so far.
> int _idx; /* internal iterator */
> for (_idx = 0; _idx < NLST; ++_idx) {
> int *i = lst[_idx];
[snip]
That's the C idiom
for i in range(len(lst))
we all complain about here. How about (untested):
/*
iterate over the list, binding i to each item in succession;
_idx is internal to the interpreter;
separate the definition of i from the assignment of i for clarity
*/
int **_idx;
for( _idx = lst; _idx < lst + NLST; ++_idx ) {
int *i;
i = *_idx;
/* compare "the item to which i is bound" to "a constant" */
if( *i == *(&_i2) )
/* rebind i to _i4 */
i = &_i4;
}
> for (_idx = 0; _idx < NLST; ++_idx)
> printf("%d\n",*lst[_idx]);
for( _idx = lst; _idx < lst + NLST; ++_idx ) {
int *i = *_idx;
printf( "%d\n", *i );
}
Regards,
Dan
--
Dan Sommers
<http://www.tombstonezero.net/dan/>
--
http://mail.python.org/mailman/listinfo/python-list
