In article <[EMAIL PROTECTED]>,
Raven <[EMAIL PROTECTED]> wrote:
>Well, what to say? I am very happy for all the solutions you guys have
>posted :-)
>For Paul:
>I would prefer not to use Stirling's approximation
>
>
>The problem with long integers is that to calculate the hypergeometric
>I need to do float division and multiplication because integer division
>returns 0. A solution could be to calculate log(Long_Factorial_Integer)
.
.
.
This thread confuses me.
I've lost track of the real goal. If it's an exact calculation of
binomial coefficients--or even one of several other potential
targets mentioned--I echo Steven D'Aprano, and ask, are you *sure*
the suggestions already offered aren't adequate? Also, I think you
might not realize how accurate Stirling's approximation (perhaps to
second order) is in the range of interest.
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