Tim Hochberg wrote: > g=''.join;seven_seg=lambda i:g( > g(' _|x|'[ord("~$]m'k{d\x7fo"[int(n)])>>s&j] > for n in i for j in(2,1,4))+'\n'for s in(6,0,3)) > > I've replaced the unprintable characters and added some preemptive > linebreaks so that hopefully this won't get too munged. It's all clear > now, right? Two hints: 6,0,3->row, 2,1,4->column and the 6 and 1 have to > be where they are to exploit the property that the top row only ever has > a center character in it. That way things can be encoded in 7-bits and > fit in a character string that Python likes. The order of the other loop > indices is mostly accidental but not all permutations may work.
I worked on a similar solution, but didn't have the idea of iterating over a series of masks as you did with the 'j' variable. Good work. > I'm off to try to figure out how to do it the other way now, before the > code gets revealed. We should have more contests like this. While the skills I applied for the contest don't have much practical value, the mental exercise was great. Shane -- http://mail.python.org/mailman/listinfo/python-list