Pseudo-XPath support for ElementTree with the emphasis on 'Pseudo'.
http://gflanagan.net/site/python/pagliacci/ElementFilter.html
It's an approach suggested by the Specification Pattern
eg. http://www.martinfowler.com/apsupp/spec.pdf
Not tested beyond what follows (no time for more at the minute).
Criticisms and suggestions are welcome.
(one possibly obvious 'feature' is that '[EMAIL PROTECTED]'[EMAIL PROTECTED]']'
won't work, ie. if the name of an attribute is contained within a query
string, and is preceded by an '@' character)
Gerard
xml_test ='''
<mail:Mail xmlns:mail="xmlns1">
<mail:Date>10/10/05</mail:Date>
<mail:From address='[EMAIL PROTECTED]' name='Mr. Jones'/>
<mail:Subject>just a note</mail:Subject>
<mail:To>
<mail:mailto address='[EMAIL PROTECTED]' name='Mrs Jones' test='3' />
<mail:mailto address='[EMAIL PROTECTED]' name='Mr Smith' test='1'/>
</mail:To>
<mail:To>
<mail:mailto address='[EMAIL PROTECTED]' name='Mrs Jones' test='2'/>
</mail:To>
<mail:Cc></mail:Cc>
<mail:Body>hi there,
just a note to say hi there!</mail:Body>
<mail:Attachments></mail:Attachments>
</mail:Mail>
'''
if __name__ == '__main__':
print '##########'
from elementtree import ElementTree
from elementtree.ElementTree import dump
root = ElementTree.fromstring( xml_test )
ns = "xmlns1"
path = r"{%s}To/[EMAIL PROTECTED]'Mrs Jones' and @test==3]" %
(ns,ns)
filter = ElementFilter(path)
print filter.path
nodeset1 = filter.findall( root )
for node in nodeset1:
dump(node)
print '-'*30
filter.path = r"{%s}To/[EMAIL PROTECTED]<3]" % (ns,ns)
print filter.path
nodeset2 = filter.findall( root )
for node in nodeset2:
dump(node)
print '-'*30
assert nodeset1 != nodeset2
assert filter.findall( root ) != []
filter.removeall( root )
assert filter.findall( root ) == []
dump(root)
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