"TY" <[EMAIL PROTECTED]> wrote: > I have this little simple script: > > for i in range(10): > for j in range(5000000): pass # Timing-delay loop > print i > > When you run it, it behaves as you would expect -- it prints 0 <pause> > on the next line prints 1 <pause> on the next line prints 2 <pause> > etc. > > But if you add a comma at the end of print statement on the last line > like this: > > for i in range(10): > for j in range(5000000): pass # Timing-delay loop > print i, > > Now it does this: > > <long pause> then prints 0 1 2 3 4 5 6 7 8 9 all at once. > > Why????? > > How can I make it to print each numbers on the same line with pauses in > between them?
because stdout is line buffered. try this instead: import time, sys for i in range(10): time.sleep(0.8) # seconds; tune as necessary print i, sys.stdout.flush() # flush stdout print </F> -- http://mail.python.org/mailman/listinfo/python-list