Gregory Piñero wrote: > Here's a question about your functions. if I only look at the keys in > freq2 then won't I miss any keys that are in freq1 and not in freq2?
No. As I start with a copy of freq1, all keys of freq1 are already there. There is probably a loop involved, but it in Python's underlying C implementation, which is a bit faster. What is left to do is to (1) add key and value for the 20% of freq2 that are not in freq1, and to (2) increase the value for the 80% where the key occurs in both freq1 and freq2. This is done by the for-loop. Peter -- http://mail.python.org/mailman/listinfo/python-list
