Antoon Pardon wrote:
> So lets agree that tree['a':'b'] would produce a subtree. Then
> I still would prefer the possibility to do something like:
>
> for key in tree.iterkeys('a':'b')
>
> Instead of having to write
>
> for key in tree['a':'b'].iterkeys()
>
> Sure I can now do it like this:
>
> for key in tree.iterkeys('a','b')
>
> But the way default arguments work, prevents you from having
> this work in an analague way as a slice.
How so? Can't you just pass the *args to the slice contstructor? E.g.::
def iterkeys(self, *args):
keyslice = slice(*args)
...
Then you can use the slice object just as you would have otherwise.
STeVe
--
http://mail.python.org/mailman/listinfo/python-list
