Fredrik Lundh wrote:
> Harald Karner wrote:
>>>python -c "print len('m' * ((2048*1024*1024)-1))"
>>
>>2147483647
>
>
> the string type uses the ob_size field to hold the string length, and
> ob_size is an integer:
>
> $ more Include/object.h
> ...
> int ob_size; /* Number of items in variable part */
> ...
>
> anyone out there with an ILP64 system?
I have access to an itanium system with a metric ton of memory. I
-think- that the Python version is still only a 32-bit python, though
(any easy way of checking?). Old version of Python, but I'm not the
sysadmin and "I want to play around with python" isn't a good enough
reason for an upgrade. :)
Python 2.2.3 (#1, Nov 12 2004, 13:02:04)
[GCC 3.2.3 20030502 (Red Hat Linux 3.2.3-42)] on linux2
Type "help", "copyright", "credits" or "license" for more information.
>>> str = 'm'*2047*1024*1024 + 'n'*2047*1024*1024
>>> len(str)
-2097152
Yes, that's a negative length. And I don't really care about rebinding
str for this demo. :)
>>> str[0]
Traceback (most recent call last):
File "<stdin>", line 1, in ?
IndexError: string index out of range
>>> str[1]
Traceback (most recent call last):
File "<stdin>", line 1, in ?
IndexError: string index out of range
>>> str[-1]
Traceback (most recent call last):
File "<stdin>", line 1, in ?
SystemError: error return without exception set
>>> len(str[:])
-2097152
>>> l = list(str)
>>> len(l)
0
>>> l
[]
The string is actually created -- top reports 4.0GB of memory usage.
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