Hey-ho,

I'm getting a bit out of my depth porting the 'tiny encryption algorithm' 
from C to python.

Ref: 
http://en.wikipedia.org/wiki/Tiny_Encryption_Algorithm
http://www.simonshepherd.supanet.com/source.htm#new_ansi

Specifically I don;t know how to handle a C-long block and perform the
mathmatical manipulations in python syntax.  I played with pack and unpack
(from struct module) but that didn't seem to buy me anything.

In my version, I end up with hugely long integers, which have obviously
not be constrained into the 4-byte unsigned longs that TEA is expecting.

This is the C function:

/* v is 64-bits input, w is 64-bits output, k is the 128-bit key */
void decipher(const unsigned long *const v,unsigned long *const w, const 
unsigned long * const k)
{
   register unsigned long 
y=v[0],z=v[1],sum=0xC6EF3720,delta=0x9E3779B9,n=32;

   while(n-->0)
  {
      z -= (y << 4 ^ y >> 5) + y ^ sum + k[sum>>11 & 3];
      sum -= delta;
      y -= (z << 4 ^ z >> 5) + z ^ sum + k[sum&3];
  }
   w[0]=y; w[1]=z;
}


Which gives me a (broken) python version:

def  teaDecipher(input,key):
    y = input[0]
    z = input[1]
    n = 32
    sum = 0xC6EF3720
    delta=0x9E3779B9 

    while (n > 0):
        n -= 1
        z -= (y << 4 ^ y >> 5) + y ^ sum + key[sum>>11 & 3];
        sum -= delta;
        y -= (z << 4 ^ z >> 5) + z ^ sum + key[sum&3];
      return y,z

That seems to return hugely-long integers (around 30? digits), whereas I'd 
expect
them to max-out at 2^32.

Perhaps I'm not packing the input or the key properly.  My inputs are
just strings which I put into an integer with the ordinal value of each 
character
shifted into the correct position to make the C-long.

Something like:
    input[0] = ord(encrypted[i])<<24 + ord(encrypted[i+1])<<16 + 
ord(encrypted[i+2])<<8 + ord(encrypted[i+3])
    input[1] = ord(encrypted[i+4])<<24 + ord(encrypted[i+5])<<16 + 
ord(encrypted[i+6])<<8 + ord(encrypted[i+7])

The key is created as an array of numbers, each the ord() of the key 
character...


Anyway, that's about it.
Any help much appreciated.


thanks,
-kt



















(non-removable disclaimer below... *sigh*)
--

Please consider our environment before printing this email.

WARNING - This email and any attachments may be confidential. If received in 
error, please delete and inform us by return email. Because emails and 
attachments may be interfered with, may contain computer viruses or other 
defects and may not be successfully replicated on other systems, you must be 
cautious. Westpac cannot guarantee that what you receive is what we sent. If 
you have any doubts about the authenticity of an email by Westpac, please 
contact us immediately.

It is also important to check for viruses and defects before opening or using 
attachments. Westpac's liability is limited to resupplying any affected 
attachments.


This email and its attachments are not intended to constitute any form of 
financial advice or recommendation of, or an offer to buy or offer to sell, any 
security or other financial product. We recommend that you seek your own 
independent legal or financial advice before proceeding with any investment 
decision.

Westpac Institutional Bank is a division of Westpac Banking Corporation, a 
company registered in New South Wales in Australia under the Corporations Act 
2001 (Cth). Westpac is authorised and regulated in the United Kingdom by the 
Financial Services Authority and is registered at Cardiff in the United Kingdom 
as Branch No. BR 106. Westpac operates in the United States of America as a 
federally chartered branch, regulated by the Office of the Comptroller of the 
Currency.

Westpac Banking Corporation ABN 33 007 457 141.
-- 
http://mail.python.org/mailman/listinfo/python-list

Reply via email to