[EMAIL PROTECTED] wrote:
> Hi. Thanks for the tip. However, implementing that example, the script
> will only generate the second output "file", (or it's overwriting the
> first one), so all I get when run is "fileb".
I think your looping code has the structure
for x in ["a", "b", "c"]:
pass
print x
This will print x once after the loop has completed. By then the value of x
is "c". To fix it, move the code from /after/ the loop /into/ the loop:
for x in ["a", "b", "c"]:
print x
In the code you give that would mean that you have to indent the
try:
# ...
except:
# ...
statement one more level.
Inside that loop you want a filename and an integer value in lockstep. The
simplest way to get that is zip():
>>> for Disc, suffix in zip(xrange(2, 6, 2), "abcdefghijklmnopqrstuvwxyz"):
... Out_Dem = "out" + suffix
... print Disc, Out_Dem
...
2 outa
4 outb
Again, you have to replace the print statement by your try...except. If you
fear that you will eventually run out of suffices, here is a function that
"never" does:
>>> def gen_suffix(chars):
... for c in chars:
... yield c
... for c in gen_suffix(chars):
... for d in chars:
... yield c + d
...
>>> for i, s in zip(range(20), gen_suffix("abc")):
... print i, s
...
0 a
1 b
2 c
3 aa
4 ab
5 ac
6 ba
7 bb
8 bc
9 ca
10 cb
11 cc
12 aaa
13 aab
14 aac
15 aba
16 abb
17 abc
18 aca
19 acb
That said, reading the tutorial or an introductory book on Python never
hurts...
Peter
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