Duncan Booth wrote: > e.g. it is stable when you reverse the order: > > >>> lst = [[4,1],[4,2],[9,3],[5,4],[2,5]] > >>> list(reversed([ x[-1] for x in sorted([ (x[0],x) for x in lst ]) ])) > [[9, 3], [5, 4], [4, 2], [4, 1], [2, 5]] > >>> l1 = list(lst) > >>> l1.sort(key=operator.itemgetter(0), reverse=True) > >>> l1 > [[9, 3], [5, 4], [4, 1], [4, 2], [2, 5]] > Just curious, which one is supposed to be the right answer ? and why the second one is preferable over the first one(if both is right, assume we only care about x[0]).
Of course, there is no reason to DIY when the built-in can do the job. -- http://mail.python.org/mailman/listinfo/python-list
