[EMAIL PROTECTED] wrote:
> from time import sleep
> def foo(on):
> for e in list(on):
Just
for e in on:
#...
is better. The list() constructor defeats much of the laziness you gain by
using a generator.
> sleep(1)
> yield e
>
> def wrapper(x):
> if x < 0:
> return foo('ABC')
> else:
> return foo('XYZ')
>
> When I run this, variable three letters are shown and it takes 3
> seconds for the whole thing to complete. The problem is that the whole
> iteration is glogged up in the wrapper() function because the first
> letter is shown after 3 seconds and then all letters are shown at the
> same time.
>
> How do I wrap functions that return iterators? ...if possible.
The code you presented is OK. Your diagnosis is probably the result of a of
a misconstrued test case. Something like
for s in wrapper(1):
print s,
seems to work like you described because the text is buffered until the line
is complete. Try
for s in wrapper(1):
print s
or
import sys
for s in wrapper(1):
print s,
sys.stdout.flush() # explicitly flush the buffer
instead.
Peter
--
http://mail.python.org/mailman/listinfo/python-list
