On 15 Nov 2005 11:26:23 -0800 in comp.lang.python, "py"
<[EMAIL PROTECTED]> wrote:
>Dan Sommers wrote:
>> Just do it. If one of foo's callers passes in a non-iterable, foo will
>> raise an exception, and you'll catch it during testing
>
>That's exactly what I don't want. I don't want an exception, instead I
>want to check to see if it's an iterable....if it is continue, if not
>return an error code. I can't catch it during testing since this is
>going to be used by other people.
Then catch the exception yourself.
>>> def foo2(i):
try:
for j in i:
print j
print "Success!"
return 0
except TypeError, e:
print "Bad foo. No donut.", e
return -1
>>> joe = foo2([1,3,5,7,9])
1
3
5
7
9
Success!
>>> print joe
0
>>> bob = foo2(2)
Bad foo. No donut. iteration over non-sequence
>>> print bob
-1
>>>
Regards,
-=Dave
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