Thank you Bengt Richter and Sybren Stuvel for your comments, my little
procedure can be improved a bit in many ways, it was just a first
quickly written version (but it can be enough for a basic usage).
Bengt Richter:
>good way to prepare for split
Maybe there is a better way, that is putting in just the accepted
letters and accented letters, instead of the not accepted symbols.
>I suspect it's not possible to get '' in the list from somestring.split()
You are probably right, the algorithm used is different if you don't
give a splitting string:
>>> ' abc a '.split()
['abc', 'a']
>>> '.abc..a.'.split(".")
['', 'abc', '', 'a', '']
>does that beat the try and get versions? I.e., (untested)
Yes.
>countDict[w] = countDict.get(w, 0) + 1
I think the if-else version is the fastest, I have tested it a long
time ago... You can easely do a speed test to see if I am wrong.
Bear hugs,
bearophile
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