"Fredrik Lundh" <[EMAIL PROTECTED]> wrote: > "SU News Server" <[EMAIL PROTECTED]> wrote: > >> I've struggled with this for quite a while and I'm am just not sure >> what is going on. I have the following code >> import os >> >> def buildList( directory='/Users/mkonrad' ) >> >> dirs = [ ] >> >> listing = os.listdir(directory) >> >> for x in listing: >> if os.path.isdir(x): >> dirs.append(x) >> >> return dirs >> >> This always returns an empty list. >> Now if I change it so that directory='.' or directory=os.getcwd() >> Then it returns a list of directories. > > hint: if you're not sure what's going on in your program, adding > a print statement or two is an easy way to figure it out. like, say: > > for x in listing: > print x > if os.path.isdir(x): > dirs.append(x) >
Did that and I was just getting a bunch of [ ]. > (try this before you continue) > > : > : > : > > the problem is that os.listdir returns a list of filenames, without > the preceeding directory name. you can add an os.path.join > > for x in listing: > x = os.path.join(directory, x) > if os.path.isdir(x): > dirs.append(x) OK. This works except each entry in dirs now includes the full path. Is there an unjoin? :) I haven't spent any time trying to work this out. > > or use the glob module instead: > > listing = glob.glob(os.path.join(directory, "*")) > > hope this helps! > > </F> > > > > -- http://mail.python.org/mailman/listinfo/python-list
