Thanks for you reply.
I added locals() to my exec statment, so it worked, but I wasn't so sure
about my interpretation of the problem.
Fredrik Lundh wrote:
> N. Pourcelot wrote:
>
>
>>I can't understand some specific behaviour of the exec statment.
>>
>>For example, say that I create such a class A :
>>
>>class A:
>> def __init__(self):
>> self.n = 3
>> self.m = None
>> def h(self, ini):
>> n = self.n
>> m = self.m
>> if ini: exec("def m(x): return n+x"); self.m=m
>> else: m(7)
>>
>>Now :
>>obj = A()
>>obj.h(1)
>>obj.h(0)
>>
>>I get :
>>
>>Traceback (most recent call last):
>> File "<input>", line 1, in ?
>> File "<input>", line 9, in h
>> File "<string>", line 1, in m
>>NameError: global name 'n' is not defined
>
>
> exec only supports local and global scopes; the "n" inside the exec statement
> is a not a local, so it's assumed to be a global variable.
>
> (Python's lexical scoping requires the compiler to look for free variables in
> inner
> scopes before generating code for the outer scope; it cannot do that for
> exec, for
> obvious reasons).
>
> </F>
>
>
>
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