[EMAIL PROTECTED] writes:
> The code's indentation was fine - I forgot to declare cell in player
> two's section and not just in player one.
>
> The code (including the win check, for once!) is working. The last
> obstacle is my tie checker; it doesn't seem to like what I have:
>
> if ((gameboard[0:9] is 'X' or 'O') and (win == 0)):
> print "Tie."
> win = 2
>
> Will the [0:9] range not work in this? Should I write out each option?
> Or is there some way to check if all things in the list are NOT ' '?
>
> I tried
>
> if ((gameboard[0:9] is not ' '))
Yes, those tests are not doing what you want them to do. On the other
hand, you can still test this in one swell foop with "in":
if ' ' not in gameboard and win == 0:
print "Tie."
win = 2
That does assume that gameboard and gameboard[0:9] are the same
thing. But they should be. For that matter, the defaults for the slice
should be 0 and 9, so that gameboard[:] is the same thing yet
again. But since you're not changing the board but reading it, there's
no need to make a copy, which is what the sliced versions do.
<mike
--
Mike Meyer <[EMAIL PROTECTED]> http://www.mired.org/home/mwm/
Independent WWW/Perforce/FreeBSD/Unix consultant, email for more information.
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