beza1e1 wrote:
> let me try.
>
> 1) ''.join(lots_of_pieces)
>
> 2) This doesn't even work, if something is removed, the list is too
> short. So:
> [x for x in somelist if not isbad(x)]
> well, list comprehension is Python 2.4
2.2.x IIRC
> and 2.3 is the standard in many
> OSes, so it is possibly not the most portable solution
filter(isbad, somelist)
--
bruno desthuilliers
python -c "print '@'.join(['.'.join([w[::-1] for w in p.split('.')]) for
p in '[EMAIL PROTECTED]'.split('@')])"
--
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