Mapisto wrote: > Hi, > > I've noticed that if I initialize list of integers in the next manner: > > >>>>my_list = [0] * 30 > > > It works just fine, even if I'll try to assign one element: > > >>>>id( my_list[4] ) > > 10900116 > >>>>id( my_list[6] ) > > 10900116 > >>>>my_list[4] = 6 >>>>id( my_list[4] ) > > 10900044 > >>>>id( my_list[6] ) > > 10900116 > > The change in the poision occurs becouse int() is an immutable object.
No, it happens because you assign my_list[4] to a different object. Obviously, 0 and 6 can't be located in the same place in RAM. The difference lies in doing something like "my_list[n] = X" rather than changing the state of a shared existing object as in something like "my_list[n].f(X)". > if I will do the same with a user-defined object, This reference > manipulating will not happen. Really? >>> class C: ... pass ... >>> my_list = [C()]*30 >>> id(my_list[4]) 1003056 >>> id(my_list[6]) 1003056 >>> my_list[4] = C() # Another instance >>> id(my_list[4]) 986048 >>> id(my_list[6]) 1003056 -- http://mail.python.org/mailman/listinfo/python-list
