python-gpib provides Gpib.py (see end of post) for Linux.
I am trying to use the method called read. I usually use it without
arguments (the default length being 512). However, I am trying to read in a
string with some 16,000 comma separated floating point numbers.
So, I have to pass a length parameter much much larger than 512. As is
stands, the default read takes in only about 35-40 numbers, so I need about
512/35*16000 ~= 230,000. Not being sure if I could make python read in
something that big, I started small - with 1024. This produces an list of
numbers that has a malformed first number (I get 88309e-9 instead of
something like 6.788309e-9.).
Could this be a bug ?
Second, does the length need to be a power of two for some reason ?
python-gpib is an excellent library, but it suffers from an utter lack of
documentation.
------------------------ Gpib.py -----------------------------
import gpib
RQS = (1<<11)
SRQ = (1<<12)
TIMO = (1<<14)
class Gpib:
def __init__(self,name='gpib0'):
self.id = gpib.find(name)
def write(self,str):
gpib.write(self.id, str)
def writebin(self,str,len):
gpib.writebin(self.id,str,len)
def read(self,len=512):
self.res = gpib.read(self.id,len)
return self.res
def readbin(self,len=512):
self.res = gpib.readbin(self.id,len)
return self.res
def clear(self):
gpib.clear(self.id)
def wait(self,mask):
gpib.wait(self.id,mask)
def rsp(self):
self.spb = gpib.rsp(self.id)
return self.spb
def trigger(self):
gpib.trg(self.id)
def ren(self,val):
gpib.ren(self.id,val)
def ibsta(self):
self.res = gpib.ibsta()
return self.res
def ibcnt(self):
self.res = gpib.ibcnt()
return self.res
def tmo(self,value):
return gpib.tmo(self.id,value)
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