Scott David Daniels wrote:
> Philipp H. Mohr wrote:
>> I am trying to xor the byte representation of every char in a string with
>> its predecessor. But I don't know how to convert a char into its byte
>> representation.
> ord('a') == 97; chr(97) == 'a'; "ord" gives you the value of the byte.
>
>> e.g. everything between $ and * needs to be xor:
>> $GPGSV,3,1,10,06,79,187,39,30,59,098,40,25,51,287,00,05,25,103,44*
>> to get the checksum.
>
> Probably you want a byte-array here, rather than going char-by-char.
> Try:
> import array
> base = ('$GPGSV,3,1,10,06,79,187,39,30,59,098,'
> '40,25,51,287,00,05,25,103,44*')
> bytes = array.array('b', base[1 : -1])
> for i in reversed(range(len(bytes))):
> bytes[i] ^= bytes[i-1]
> result = bytes.tostring()
Seems like the OP doesn't need what he asked for. The simpler
def checksum(s):
assert s[0] == "$"
assert s[-1] == "*"
result = 0
for c in s[1:-1]:
result ^= ord(c)
return result
should do.
Peter
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