jena <[EMAIL PROTECTED]> writes:
> # BEGIN CODE
> def test():
> def x():
> print a
> a=2 # ***
> a=1
> x()
> print a
>
> test()
> # END CODE
>
> This code fails (on statement print a in def x), if I omit line marked
> ***, it works (it prints 1\n1\n). It look like when I assign variable
> in nested function, I cannot access variable in container function.
> I need to assign variable in container function, is any way to do this?
No, this is a big bug in Python, there's no way to specify what scope
you want. The compiler implicitly decides that since you set a to
something inside x(), a must be a local variable. The principle that
explicit is better than implicit was ignored here.
There's a kludgy workaround which is to box the variable:
def test():
def x():
print a[0]
a[0] = 2
a = [1]
print a[0]
However, the arbiters of Python style would prefer that you use a
class instance instead.
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