"CJ" wrote: > What does worry me, is that I can't seem to get the program by a > certain spot. It keeps giving me the same error, and I don't know why.
quite often, exception messages means exactly what they say; if you get an index error, it's because you're trying to fetch an item that doesn't exist. for simple debugging, the "print" statement is your friend: > ttllst=[4,3,45,3] > cnto=0 > cntt=1 > rept=-1 > > print cnto > print cntt > print ttllst[cnto] > print ttllst[cntt] > choice=raw_input("Begin? ") > if choice == "yes" or choice == "y": > while cnto<>len(ttllst)+1: print cnto, cntt, len(ttllst) > if ttllst[cnto]==ttllst[cntt]: > rept=rept+1 > if cntt==len(ttllst): > print ttllst[cnto],"appears in the list",rept,"times." > cntt=-1 > cnto=cnto+1 > rept=-1 > cntt=cntt+1 > print "done." with that in place, I get Begin? y 0 1 4 0 2 4 0 3 4 0 4 4 Traceback (most recent call last): File "test.py", line 14, in ? if ttllst[cnto]==ttllst[cntt]: IndexError: list index out of range which means that your second list index (cntt) is too large. figuring out how to fix that is left as an etc etc. </F> PS. when you've sorted this out, you might wish to check out the "count" method on list objects: >>> help(list.count) Help on method_descriptor: count(...) L.count(value) -> integer -- return number of occurrences of value -- http://mail.python.org/mailman/listinfo/python-list