On Tue, 27 Sep 2005 10:42:20 -0500, rumours say that Terry Hancock
<[EMAIL PROTECTED]> might have written:
>This works:
>
>>>> bz2.decompress(eval(repr(user)))
>'huge'
>This may have some security issues, though, since it evaluates essentially
>any expression given for user. I'd be interested to know if someone
>knows a more secure way.
given
a = "a tab\\x09between"
this is more secure than eval:
b= a.decode("string_escape")
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