On Fri, 16 Sep 2005 21:42:40 +0200, Irmen de Jong <[EMAIL PROTECTED]> wrote:
>JerryB wrote:
>> Hi,
>> I have a dictionary for counting ocurrences of strings in a document.
>> The dictionary looks like this:
>>
>> 'hello':135
>> 'goodbye':30
>> 'lucy':4
>> 'sky':55
>> 'diamonds':239843
>> 'yesterday':4
>>
>> I want to print the dictionary so I see most common words first:
>>
>> 'diamonds':239843
>> 'hello':135
>> 'sky':55
>> 'goodbye':30
>> 'lucy':4
>> 'yesterday':4
>>
>> How do I do this? Notice I can't 'swap' the dictionary (making keys
>> values and values keys) and sort because I have values like lucy &
>> yesterday which have the same number of occurrences.
>>
>> Thanks.
>>
>
>Don't try to 'swap' the dict, just sort a list based on the items in
>the dict. Try this:
>
>original= {
>'hello':135,
>'goodbye':30,
>'lucy':4,
>'sky':55,
>'diamonds':239843,
>'yesterday':4 }
>
>items = sorted( (v,k) for (k,v) in original.iteritems() )
>items.reverse() # depending on what order you want
>print items
>
>
>The result is:
>[(239843, 'diamonds'), (135, 'hello'), (55, 'sky'), (30, 'goodbye'), (4,
>'yesterday'),
>(4, 'lucy')]
>
>
or tell sorted what to do ;-)
>>> original= {
... 'hello':135,
... 'goodbye':30,
... 'lucy':4,
... 'sky':55,
... 'diamonds':239843,
... 'yesterday':4 }
>>> list(sorted(original.iteritems(), None, lambda t:t[1], True))
[('diamonds', 239843), ('hello', 135), ('sky', 55), ('goodbye', 30),
('yesterday', 4), ('lucy',4)]
Regards,
Bengt Richter
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