On 12/6/2025 2:51 PM, Em wrote:
The confusing part here is that no one has indicated whether or not the
statement fails in any of the six ways to run this program except me.
Am I the only one that as the problem?
No. I created the program with the suggested printout of the working
directory. Here's what I ran:
import os
print("Start")
print("working directory:", os.getcwd())
input(" Starter file")
try:
Starter = open("HLY-LOG5.txt","w")
except Exception as e:
print(f"Error: {e}")
input("End")
It ran but failed to create the file. That's because of the working
directory when the program was run by double-clicking its name. Here's
the output.
Start
working directory: C:\WINDOWS\system32
Starter file
Error: [Errno 13] Permission denied: 'HLY-LOG5.txt'
End
An ordinary user doesn't have permission for the C:\WINDOWS\system32
directory. Maybe on your Windows 10 system the working directory was
the program's directory. But with the new file association system it's
not. I think it should be, myself.
When I ran the program by typing just its name in a terminal opened on
the program's directory, it created the file without any errors.
I'm running Python 3.12+, but the exact version won't matter because the
initial working directory is set by Windows, not Python.
If you really really want programs that reliably write to the program's
directory, you can get it from sys.argv[0] and have Python change
directories for you. Otherwise, start your program in some other way
than by double-clicking.
-----Original Message-----
From: Peter J. Holzer <[email protected]>
Sent: Saturday, December 6, 2025 12:56 PM
To: [email protected]
Subject: Re: A switch somewhere, or bug? CORRECTION
On 2025-12-04 18:03:34 -0500, Em wrote:
^^^^^^^^^^
Weird. That was before most of the thread (and the message wasn't stuck
in a moderation queue), yet it seems everybody ignored this message. .
Probably because it isn't actually part of the thread, but ...
On my computer: Win11, Python 3.14.1
Double-click and run on the file". You will see the first two lines
execute.
The screen will show "Start" and "Starter File".
Good. So we know that the program is executed.
Hit <Enter> to resolve the
pause statement and the program crashes when it tries to create the
"HLY-LOG5" file. The last line, "End" is not printed. No file is created.
So the next step is to find out why it isn't executed. First print the
working directory:
import os
print("Start")
print("working directory:", os.getcwd())
input(" Starter file")
then wrap the open in a try/except block:
try:
Starter = open("HLY-LOG5.txt","w")
except Exception as e:
print("Error: {e}")
input("End")
This should now tell you in which directory the program is actually trying
to create the file and why it didn't work.
hip
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