import itertools
def chunk1(seq):
return [ ch * len(list(grp)) for (ch, grp) in itertools.groupby(s) ]
def chunk2(seq):
return [ (ch, len(list(grp))) for (ch, grp) in itertools.groupby(s) ]
s='aaabbccccaa'
print(chunk1(s))
print(chunk2(s))
###################################
Program output:
['aaa', 'bb', 'cccc', 'aa']
[('a', 3), ('b', 2), ('c', 4), ('a', 2)]
Rob Cliffe
On 09/06/2024 22:20, HenHanna via Python-list wrote:
Chunk, ChunkC -- nice simple way(s) to write these in Python?
(Chunk '(a a b a a a b b))
==> ((a a) (b) (a a a) (b b))
(Chunk '(a a a a b c c a a d e e e e))
==> ((a a a a) (b) (c c) (a a) (d) (e e e e))
(Chunk '(2 2 foo bar bar j j j k baz baz))
==> ((2 2) (foo) (bar bar) (j j j) (k) (baz baz))
_________________
(ChunkC '(a a b b b))
==> ((a 2) (b 3))
(ChunkC '(a a b a a a b b))
==> ((a 2) (b 1) (a 3) (b 2))
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