On 2024-03-25, Loris Bennett <loris.benn...@fu-berlin.de> wrote:
> "Michael F. Stemper" <michael.stem...@gmail.com> writes:
>
>> On 25/03/2024 01.56, Loris Bennett wrote:
>>> Grant Edwards <grant.b.edwa...@gmail.com> writes:
>>>
>>>> On 2024-03-22, Loris Bennett via Python-list <python-list@python.org>
>>>> wrote:
>>>>
>>>>> Yes, I was mistakenly thinking that the popping the element would
>>>>> leave me with the dict minus the popped key-value pair.
>>>>
>>>> It does.
>>> Indeed, but I was thinking in the context of
>>> dict_list = [d.pop('a') for d in dict_list]
>>> and incorrectly expecting to get a list of 'd' without key 'a',
>>> instead
>>> of a list of the 'd['a]'.
>> I apologize if this has already been mentioned in this thread, but are
>> you aware of "d.keys()" and "d.values"?
>>
>> >>> d = {}
>> >>> d['do'] = 'a deer, a female deer'
>> >>> d['re'] = 'a drop of golden sunshine'
>> >>> d['mi'] = 'a name I call myself'
>> >>> d['fa'] = 'a long, long way to run'
>> >>> d.keys()
>> ['fa', 'mi', 'do', 're']
>> >>> d.values()
>> ['a long, long way to run', 'a name I call myself', 'a deer, a female
>> deer', 'a drop of golden sunshine']
>> >>>
>
> Yes, I am, thank you. However, I didn't want either the keys or the
> values. Instead I wanted to remove a key within a list comprehension.
Do you mean something like:
[my_dict[key] for key in my_dict if key != 'a']
?
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