def powers_of_2_in(n):
s = 0
while n % 2 == 0:
s += 1
n = n // 2
return s, n
> On 30 Nov 2023, at 02:44, Julieta Shem via Python-list
> <python-list@python.org> wrote:
>
> How would you write this procedure?
>
> --8<---------------cut here---------------start------------->8---
> def powers_of_2_in(n):
> s = 0
> while "I still find factors of 2 in n...":
> q, r = divmod(n, 2)
> if r == 0:
> s = s + 1
> n = n // 2
> else:
> return s, n
> --8<---------------cut here---------------end--------------->8---
> --
> https://mail.python.org/mailman/listinfo/python-list
--
https://mail.python.org/mailman/listinfo/python-list
