MRAB makes a valid point. The regular expression compiled is only done on the
pattern you are looking for and it it contains anything that might be a
command, such as an ^ at the start or [12] in middle, you want that converted
so NONE OF THAT is one. It will be compiled to something that looks for an ^,
including later in the string, and look for a real [ then a real 1 and a real 2
and a real ], not for one of the choices of 1 or 2.
Your example was 'cty_degrees + 1' which can have a subtle bug introduced. The
special character is "+" which means match greedily as many copies of the
previous entity as possible. In this case, the previous entity was a single
space. So the regular expression will match 'cty degrees' then match the single
space it sees because it sees a space followed ny a plus then not looking for
a plus, hits a plus and fails. If your example is rewritten in whatever way
re.escape uses, it might be 'cty_degrees \+ 1' and then it should work fine.
But converting what you are searching for just breaks that as the result will
have a '\+" whish is being viewed as two unrelated symbols and the backslash
breaks the match from going further.
-----Original Message-----
From: Python-list <python-list-bounces+avi.e.gross=gmail....@python.org> On
Behalf Of MRAB
Sent: Monday, February 27, 2023 6:46 PM
To: python-list@python.org
Subject: Re: How to escape strings for re.finditer?
On 2023-02-27 23:11, Jen Kris via Python-list wrote:
> When matching a string against a longer string, where both strings have
> spaces in them, we need to escape the spaces.
>
> This works (no spaces):
>
> import re
> example = 'abcdefabcdefabcdefg'
> find_string = "abc"
> for match in re.finditer(find_string, example):
> print(match.start(), match.end())
>
> That gives me the start and end character positions, which is what I want.
>
> However, this does not work:
>
> import re
> example = re.escape('X - cty_degrees + 1 + qq') find_string =
> re.escape('cty_degrees + 1') for match in re.finditer(find_string,
> example):
> print(match.start(), match.end())
>
> I’ve tried several other attempts based on my reseearch, but still no match.
>
> I don’t have much experience with regex, so I hoped a reg-expert might help.
>
You need to escape only the pattern, not the string you're searching.
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